Select all the expressions that are equal to the product of 8 and 10

Which equation has a solution of x = -5?

lyudmila [28]

The first equation has a solution of X=-5

3 0

2 years ago

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Heelllppp please!!!!!!!

Brums [2.3K]

Answer:

7.9

Step-by-step explanation:

area of circle equals π× 5 = 15.7

area of half of the circle equals 15.7÷2

=7.85

now round it of and it's 7.9

8 0

2 years ago

3+2⋅[(2+1)⋅5+8] need the answer please

s2008m [1.1K]

Hey!

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Solution:

Remember to follow PEMDAS!

= 3 + 2 ⋅ [(2 + 1) ⋅ 5 + 8]

= 3 + 2 ⋅ [(3) ⋅ 5 + 8]

= 3 + 2 ⋅ [(15) + 8]

= 3 + 2 ⋅ [23]

= 3 + 46

= 49

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Answer:

49

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Hope This Helped! Good Luck!

8 0

2 years ago

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Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

3 years ago

3200 dollars is placed in an account with an annual interest rate of 8.25%. To the nearest tenth of a year, how long will it tak

Whitepunk [10]

Answer:

24.2 years

Step-by-step explanation:

The basic formula is I = P * i * t, where I is interest, P is total principal (or profit), i is rate of interest per year, and t is total time in years. I = P * i * t can be rearranged to solve for t: t = I / (i * p).

In this question I = $6400, P = $3200 and i = 8.25%, so we plug in those numbers to get t = 6400 / (0.0825 * 3200), which solves to 24.2424 years.

3 0

3 years ago