An airplane cabin is pressurized to 570 mmhg. what is the pressure inside the cabin in atmospheres?

2 answers:

8 0

1 atm corresponds to 760 mmHg, so we can set up a simple proportion to find how many atmospheres correspond to 570 mmHg:
$1 atm: 760 mmHg = x: 570 mmHg$
and from this, we find
$x= \frac{1 atm \cdot 570 mmHg}{760 mmHg} =0.75 atm$

OLEGan [10]2 years ago

7 0

Answer:

0.75 atmospheric pressure

Explanation:

Pressure, P = 570 mm of Hg

We know that 1 atmospheric pressure = 760 mm of Hg

So, 760 mm of Hg pressure = 1 atmospheric pressure

1 mm of Hg = 1 / 760 atm pressure

570 mm of Hg = 570 / 760 atm

= 0.75 atm

Thus, 570 mm of Hg pressure is equal to 0.75 atmospheric pressure.

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tino4ka555 [31]

Answer:

2) c) give-way vessel

3) a) With one short blast

Explanation:

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In overtaking, the vessel intending to overtake is the Give-Way Vessel the vessel that is going to be overtaken is the Stand-On Vessel

Therefore, the correct option is c) give-way vessel

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2 years ago

A 7.7 kg sphere makes a perfectly inelastic collision with a second sphere initially at rest. The composite system moves with a

klemol [59]

Answer:

15.4 kg.

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m').................... Equation 1

Where m = mass of the first sphere, m' = mass of the second sphere, u = initial velocity of the first sphere, u' = initial velocity of the second sphere, V = common velocity of both sphere.

Given: m = 7.7 kg, u' = 0 m/s (at rest)

Let: u = x m/s, and V = 1/3x m/s

Substitute into equation 1

7.7(x)+m'(0) = 1/3x(7.7+m')

7.7x = 1/3x(7.7+m')

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m' = 23.1-7.7

m' = 15.4 kg.

Hence the mass of the second sphere = 15.4 kg

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2 years ago