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2 years ago

How to work 11a-5c+3a

Mathematics

2 answers:

Dvinal [7]2 years ago

7 0

Your final answer would be 14a-5c

Vikki [24]2 years ago

6 0

11a - 5c + 3a

1. Combine like terms

11a + 3a = 14a

14a - 5c

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Give your answer in minutes.

Illusion [34]

In an hour there are 60 minutes.

6:38 PM + 22minutes = 7 PM
From 7 PM to 7:23 PM there are 23 minutes

So, (23 + 22) minutes = 45 minutes.

5 0

1 year ago

Read 2 more answers

Hello people ~

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

apply chain rule

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

Equate the first derivative to zero, that is V'(x) = 0

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$

maximum volume: when h = 40/3

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

minimum volume: when h = 0

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

1 year ago

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Keegan leans an 18-foot ladder against the top of a wall. The bottom of the ladder is 4.5 feet from the base of the wall. What i

zaharov [31]

Answer: C. 17.5 feet

Step-by-step explanation:

The attached photo shows the triangle ABC formed by the ladder and the wall. It is a right angle triangle because one of its angles is 90 degrees. The ladder is the hypotenuse of the triangle. To determine the height of the wall, we would find BC by applying Pythagoras theorem

Hypotenuse^2 = opposite ^2 + adjacent^2

18^2 + 4.5^2 + BC^2

BC^2 = 324 - 20.25 = 303.75

BC = √303.75 = 17.5 feet.

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2 years ago

Hurry! might mark brainliest! what is this in slope-intercept form?

Angelina_Jolie [31]

Y=2/3x

The y-intercept is zero, and the slope is 2/3

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2 years ago

A construction company wants to hire x carpenters for $220 a day and y plumbers for $260 a day. the company wants to hire at lea

Ksju [112]

Answer:6

Step-by-step explanation:

$220 × 6 = $1320 this is how much it cost to pay 6 carpenters for one day. Now lets find how much it cost to 12 plumbers at $260 a day. $260 × 12 = $3120 this is how much it costs to pay 12 plumbers a day.

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2 years ago