1/4, 8/15, 6/5
One way to figure this out is to divide the fractions and find which number is bigger
Or you should know 1/4= .25 , 8/15 is around half or .5 and 6/5 the numerator is larger than the denominator, so it would be bigger than 1 <span />
The correct answer is C. 2 3/8 yd.
I hope that helped you! c:
Answer:
-3
Step-by-step explanation:
To find the average of different numbers, first you add them all up. So -5+-7+-2+2+-3+=-15. Then, you divide the sum of all the numbers by the amount of numbers there were. So in this case, there were 5 numbers so we would divide the sum of all of them by 5. So now we do -15/5=-3.
Another example of finding the average of numbers is 15+4+10+9+3+1. So first we add them up and we get 42, then again, we divide by the amount of numbers there are. So we do 40/6 and we get 7, so the average is 7.
I hope this helped.
C. 2+3 = 5
1/12+1/12=2/12
So C would make sense because those all add up to the answer :-)
Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)