<span>boron trichloride + water → boric acid + hydrochloric acid</span>
Answer: The volume of the balloon when it is fully cooled by my refrigerator is 0.3 L
Explanation:
To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
Putting values in above equation, we get:
Thus the volume of the balloon when it is fully cooled by my refrigerator is 0.3 L
Answer:
The simplified mechanism and products are on the picture.
Explanation:
If we have the symmetrical alkene the addition of mercury and OH group is not regioselective but when we have more donors for one of Carbons in alkene then the OH group will go there.
Answer:
1) single replacement
2) combustion reaction.
3) double replacement reaction
4) combination reaction
5) decomposition reaction
Explanation:
Chemical equation:
Fe₂CO₃ + 3C → 2Fe + 3CO
The given reaction is single replacement reaction. In this reaction carbon react with Fe₂CO₃ and replace the iron from CO₃²⁻ and form free iron and carbon monoxide.
Chemical equation:
C₂H₄ + 3O₂ → 2CO₂ + 2H₂O
The given reaction is combustion reaction. In which ethene burn in the presence of oxygen form carbon dioxide and water.
Chemical equation:
Fe₂O₃ + 6HCl → 2FeCl₃ + 3H₂O
The given reaction is double replacement reaction. In which anion and cation of both reactants exchange with each others.
Chemical equation:
2Al + 2Br₂ → 2AlBr₃
The given reaction is combination reaction in which aluminium and bromine combine to form aluminium bromide.
Chemical equation:
C₆H₁₂O₆ → 6C + 6H₂O
The given reaction is decomposition reaction in which glucose molecule decompose to give water and carbon.
Answer:
(a) 282 kJ
(b) 67.4 Calories
Explanation:
(a) The molar enthalpy, ΔH = −2802.5 kJ/mol, means that the heat produced by the reaction is 2802.5 kJ per mol of glucose.
We can multiply the enthalpy by the number of moles of glucose to get the heat produced by the metabolism. Grams of glucose will be converted to moles using the molar mass of glucose (180.156 g/mol):
(18.1 g)(mol/180.156g)(2802.5 kJ/mol) = 282 kJ
(b) Using the result we obtained above, kJ will be converted to Calories using the conversion factor of 4.184J = 1 cal. Calorie with a capital C is the same as a kilocalorie.
(282 kJ)(1 cal/4.184J) = 67.4 kcal = 67.4 Calories