Triangle:
Area = 1/2*b*h
= (1/2)*3*4
= 3*2
= 6 m^2
7a.
1cm^3
Or, 1cm * 1cm * 1cm
Or, 10mm * 10 mm * 10 mm
Or, 1000 mm^3
7b.i)
10 cm^3
Or, 10cm * 1cm* 1cm
Or, 100mm * 10mm * 10mm
Or, 10000 mm^3
8.)
Volume = 50 cm^3
Base area= 5 cm^2
Now,
Volume = area * height
Or, 50 = 5 * height
Or, height = 50/5
Or, height = 10 cm
Plz mark this as the brainiest. :)
X=5 and y =2.
Here's how you do it.
Multiply the first equation by -3, and the second one by 1.
add the equations to eliminate x.
then solve for y by dividing both sides by -5, which gives us 2.
to solve for x subsitute 2 in for y.
Answer:
the answer is- 0.09
Step-by-step explanation:
You sound smart!
Answer:
c, e, f, and i
Step-by-step explanation:
a. is bounded above at y = 1 and below at y = 0
b. is unbounded both above and below
c. is bounded below at y = 0 and unbounded above
d. is unbounded both above and below
e. is bounded below at y = 0 and unbounded above
f. is bounded below at y = 0 and unbounded above
g. is bounded below at y = 0 and bounded above at y = 1
h. is unbounded both above and below
i. is bounded below at y = 0 and unbounded above
j. is unbounded both above and below
It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}