Answer:
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Step-by-step explanation:
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We have
k^2 - 25f^2 + 5kf - 25f^2 =
k^2 - (5f)^2 + 5f( k - 5f) =
( k - 5f )( k + 5f ) + 5f( k - 5f ) =
( k - 5f )( k + 5f + 5f ) =
( k - 5f )( k + 10f );
The standard deviation for the sample mean distribution=0.603
We are given that
Mean,
Standard deviation,
n=44
We have to find the standard deviation for the sample mean distribution using Central Limit Theorem for Means.
Standard deviation for the sample mean distribution
Using the formula
Hence, the standard deviation for the sample mean distribution=0.603
0.85
total samples cases = 20
chances that are even or odd prime are 17 chances
2, 3, 4, 5, 6, 7, 8, 10, 11, 12, 13, 14, 16, 17, 18, 19, 20
probability = 17/20
= 0.85