Explanation:
The required concentration of M1 =0.222 M.
The required volume of is V1 =225 mL.
The standard solution of is M2 =16 M.
The volume of standard solution required can be calculated as shown below:
Since the number of moles of solute does not change on dilution.
The number of moles
Hence, 3.12 mL of 16 m nitric acid is required to prepare 0.222 M and 225 mL of nitric acid.
Answer:
0.535 = 55.04816695 grams
Explanation:
0.009718761398284852 moles = 1 gram
Is soluble in water but not soluble in acetonitrile.
So i think its false
The name come from the German 'Bisemutum' a corruption of 'Weisse Masse' meaning white mass.
2AgCl (s) + Ba(NO3)2 (aq)