The LCM of 4,10 and 12 is 60.
Answer:
Option 1: 0.32
Step-by-step explanation:
Let
P(A) be the experimental probability of getting two
And
P(B) be the experimental probability of getting three
The dice is rolled 360 times.
So the sample space is n(S) = 360
P(A) = n(A)/n(S)
= 54/360
= 0.15
And
P(B) = n(B)/n(S)
= 62/360
= 0.172
As both the events A and B are mutually exclusive,
P(A or B) = P(A) + P(B)
= 0.15 + 0.172
=0.322
Rounding of to one decimal gives us:
0.32
So the probability of rolling a two or three is 0.32 ..
They won 14 games. If you subtract 2 ( the ties ) you are left with 22. Subtract 6 ( games more won than loss) you get 16. Then divide by two and get 8. 8 + 6 = 14.
