The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
Read more about exponential functions at:
brainly.com/question/11464095
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Step-by-step explanation:
Based on the given conditions,
Formulate:(100-80)÷80
Calculate the sum or difference:20/80
Cross out the common factor:1/4
Multiply a number to both the numerator and the denominator:1/4×25/25
Write as a single fraction :25/4×25
Calculate the product or quotient :25/100
Rewrite a fraction with denominator equals 100 to a percentage:25%
Answer : 25%
Answer:
you times that by 7 I think
Step-by-step explanation:
Answer:
I think that there is indefinite.
Step-by-step explanation:
The reason why is because <em>x and y </em>could be any number
