For you to do area it is length times width.
First lets see the pythagorean identities
So if we have to solve for sin theta , first we move cos theta to left side and then take square root to both sides, that is
Now we need to check the sign of sin theta
First we have to remember the sign of sin, cos , tan in the quadrants. In first quadrant , all are positive. In second quadrant, only sin and cosine are positive. In third quadrant , only tan and cot are positive and in the last quadrant , only cos and sec are positive.
So if theta is in second quadrant, then we have to positive sign but if theta is in third or fourth quadrant, then we have to use negative sign .
Answer:
n = -45
Step-by-step explanation:
(n-5) /10 = -5
Multiply each side by 10
(n-5) /10 *10= -5*10
n-5 = -50
Add 5 to each side
n-5+5 = -50+5
n = -45
Find slope first:
m =y2-y1/x2-x1
m = 1--2/2--2
m = 3/4
Select a point, insert your slope, & put it into point slope form:
y-y1 =m(x-x1)
Your final answers are:
y-1=3/4(x-2)
OR
y+2 =3/4(x+2)
C = what ever the algebraic pharse is standing for c can equal to what ever number there is