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2 years ago

Adding and subtracting fractions

Mathematics

1 answer:

kakasveta [241]2 years ago

3 0

Answer:

Step-by-step explanation:

add the top of one and the bottom of the other then the top of the other and the bottom of one

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PLS HELP ME.

yarga [219]

Answer:

15092cm^3

Step-by-step explanation:

The total thickness of the strip of metal sheet would be 2*10=20cm

the new radius of the cylinder would be 9/2+20=24.5cm

Volume of a cylinder: ((pi)r^2)h

the height is 8cm

Volume : (22/7)*24.5^2*8

=15092cm^3

7 0

2 years ago

50 POINTS!! What is the sum of the first four composite numbers? 19 20 27 28

Nataliya [291]

its 27

hope this helps

6 0

2 years ago

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Keelah's clothing store bicycles for $50 and then sells them for $80 what is the percent of markup on the price of the coat

kondaur [170]

Answer:

62.5%

Step-by-step explanation:

We can write a proportion. We know that $50 is the original value and $80 is the marked up price. We don't know the marked up percentage. Let's call it x. We write equal ratios of $\frac{x}{100}$ comparing percent and $\frac{50}{80}$ comparing the 50 to the marked up price. We then set them equal.

$\frac{x}{100} =\frac{50}{80}$

We then cross multiply across the equal sign from numerator to the opposite numerator.

80(x)=50(100)

80x=5000

We divide to find x.

x=62.5

This means the bicycles are marked up 62.5% and the original value is 37.5%.

8 0

2 years ago

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

Step-by-step explanation:

Part A

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

Part B

$g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$

Part C

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0

2 years ago

There are 20 packages of beef in a restaurant freezer. The average weight of 14 of the packages is 2 lb. The remaining packages

Shtirlitz [24]

I belive that the answer is about 180 lb.

3 0

2 years ago

Read 2 more answers