A 750 kg car is moving at 20.0 m/s at a height of 5.0 m above the bottom of a hill when it runs out of gas. From there, the car
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Answer:
The time for final 15 cm of the jump equals 0.1423 seconds.
Explanation:
The initial velocity required by the basketball player to be able to jump 76 cm can be found using the third equation of kinematics as
where
'v' is the final velocity of the player
'u' is the initial velocity of the player
'a' is acceleration due to gravity
's' is the height the player jumps
Since the final velocity at the maximum height should be 0 thus applying the values in the above equation we get
Now the veocity of the palyer after he cover'sthe initial 61 cm of his journey can be similarly found as
Thus the time for the final 15 cm of the jump can be found by the first equation of kinematics as
where symbols have the usual meaning
Applying the given values we get
Answer : The force will be 4501.9
We can see that, two forces acting on the dummy in two different direction.
We know that, here two forces are given in perpendicular direction with each other.
We know the force is the vector addition law so, we will use the Pythagoras theorem for the resultant of the vectors
Now, the net force is
Two forces is given,
Now, the net force is
Hence, the force will 4501.9 N