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2 years ago

26.0 g of a liquid that has a density of 1.44 g/mL needs to be measured out in a graduated cylinder. what volume should be used

2 answers:

4 0

As Density = Mass/Volume
Mass = 26.0g
Density = 1.44g/mL
Therefore Volume = Mass/Density
=> Volume = 26.0/1.44 = 18.055... = 18.1mL (to 3 sig figs)

xenn [34]2 years ago

4 0

<u>Answer:</u> The volume of liquid used will be 18.055 mL.

<u>Explanation:</u>

To calculate the volume of liquid, we use the equation for density which is:

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$

We are given:

Mass of the liquid = 26 g

Density of the liquid = 1.44 g/mL

Volume of the liquid = ? mL

Putting values in above equation, we get:

$1.44g/mL=\frac{26g}{\text{Volume of the liquid}}\\\\\text{Volume of the liquid}=18.055mL$

Hence, the volume of liquid used will be 18.055 mL.

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I don't know but look on the internet or use a calculator

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2 years ago

Read 2 more answers

How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?

balu736 [363]

The given question is incomplete. The complete question is:

How much heat is produced when 24.8 g of $CH_4$ is burned in excess oxygen gas

Given: $CH _4
+2O_2\rightarrow CO_2+2H_2O$ ΔH= −802 kJ.

Answer: 1243.1 kJ

Explanation:

Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.

Given :

Amount of heat released on combustion of 1 mole of methane = 802 kJ kJ/mol

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

1 mole of $CH_4$ weighs = 16 g

Thus we can say:

16 g of $CH_4$ on combustion releases heat = 802 kJ

Thus 24.8 g of $CH_4$ on combustion releases = $\frac{802}{16}\times 24.8=1243.1kJ$

Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ

4 0

2 years ago

When balancing a chemical equation, what are the large numbers that we adjust?

Nata [24]

Answer:

Coefficients

Explanation:

Chemical equations are first written as a skeleton equation, which includes how many atoms each element and compound has. Skeleton equations are not 'balanced' because the number of atoms of each element on the left side (reactants) is not equal to the right side (products).

To balance a chemical equation, you can write coefficients in front of single elements and compounds. The coefficient multiplies with each single element and with each element in the compound.

For example, in this skeleton equation:

H₂ + Cl₂ => HCl

Reactants: Products:

2 hydrogen 1 hydrogen

2 chlorine 1 chlorine

Write the coefficient 2 in the products.

H₂ + Cl₂ => 2HCl

Now both reactant and product sides have 2 chlorine and 2 hydrogen, so the equation is balanced.

6 0

2 years ago

Chloroform flows through a 4.26 inch inside-diameter pipe at the rate of 3.60 gallons per minute. What is the average velocity o

Pani-rosa [81]

Answer:

1) 0,081 ft/s

2) 0,746 lb/s

Explanation:

The relation between flow and velocity of a fluid is given by:

Q=Av

where:

Q, flow [ft3/s]
A, cross section of the pipe [ft2]
v, velocity of the fluid [ft/s]

To convert our data to appropiate units, we use the following convertion factors:

1 ft=12 inches

1 ft3=7,48 gallons

1 minute=60 seconds

So,

$Q=\frac{3,60 gallons}{1 min}*\frac{1min}{60 s}*\frac{1ft3}{7,48gallons}=0,00802 \frac{ft3}{s}$

As the pipe has a circular section, we use A=πd^2/4:

$d=4,26 inch *\frac{1ft}{12 inch}=0,355ft\\ A=\pi \frac{0,355^{2} }{4}=0,0989ft2$

Finally:

Q=vA......................v=Q/A

$v=\frac{0,00802ft^{3} /s}{0,0989ft^{2} }=0,081ft/s$

The following formula is used to calculate the specific gravity of a material:

SG = ρ / ρW

where:

SG = specific gravity,

ρ = density of the material [lb/ft3]

ρW = density of water [lb/ft3] = 62.4 lbs/ft3

then:

ρ = SG*ρW = 1,49* 62,4 lb/ft3 = 93 lb/ft3

To calculate the mass flow, we just use the density of the chloroform in lb/ft3 to relate mass and volume:

$0,00802 \frac{ft3}{s}*\frac{93lb}{1ft3}=0,746lb/s$

7 0

2 years ago

The molarity of a solution prepared by dissolving 4.11 g of NaI in enough water to prepare 312 mL of solution is

Dimas [21]

Answer:

The correct answer is 8.79 × 10⁻² M.

Explanation:

Based on the given information, the mass of NaI given is 4.11 grams. The molecular mass of NaI is 149.89 gram per mole. The moles of NaI can be determined by using the formula,

No. of moles of NaI = Weight of NaI/ Molecular mass

= 4.11 / 149.89

= 0.027420

The vol. of the solution given is 312 ml or 0.312 L

The molarity can be determined by using the formula,

Molarity = No. of moles/ Volume of the solution in L

= 0.027420/0.312

= 0.0879 M or 8.79 × 10⁻² M

6 0

2 years ago