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2 years ago

Questions Answer all please

Chemistry

1 answer:

dybincka [34]2 years ago

6 0

Answer:

Both,

Vertical

Explanation:

When you push a lawn mower, you can be moving up and down or across, when your pushing a wheel barrel you can do the same, when you do a push up your going up and down which is vertical.

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In the chemical reaction C + H20 = CO + H2, what are the

drek231 [11]

B , your products are on the right side of the reaction. The reactants are on the left side

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2 years ago

Rank the organic compounds from most soluble to least soluble. To rank items as equivalent, overlap them.

denpristay [2]

The answer to your questions is as follows:

most soluble
>CH3CH2OH
>CH3OCH3
>CH3CH3
<span>least soluble
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!

7 0

2 years ago

Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonatio

Over [174]

Answer:

Most substituted alkene is produced as a major product

Explanation:

Dehydration of 3-methyl-2-butanol proceeds through E1 mechanism to form alkenes.
Most substituted alkene is produced as major product because of presence of highest number of hyperconjugative hydrogen atoms corresponding to the produced double bond (Saytzeff product).
Here, a H-shift also occurs in one of the intermediate step during dehydration to produce more stable tertiary carbocation.
Reaction mechanism has been shown below.

4 0

2 years ago

The vapor pressure of ethanol is 30°C at 98.5 mmHg and the heat of vaporization is 39.3 kJ/mol. Determine the normal boiling poi

Gelneren [198K]

Answer : The normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

Explanation :

The Clausius- Clapeyron equation is :

$\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = vapor pressure of ethanol at $30^oC$ = 98.5 mmHg

$P_2$ = vapor pressure of ethanol at normal boiling point = 1 atm = 760 mmHg

$T_1$ = temperature of ethanol = $30^oC=273+30=303K$

$T_2$ = normal boiling point of ethanol = ?

$\Delta H_{vap}$ = heat of vaporization = 39.3 kJ/mole = 39300 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

$\ln (\frac{760mmHg}{98.5mmHg})=\frac{39300J/mole}{8.314J/K.mole}\times (\frac{1}{303K}-\frac{1}{T_2})$

$T_2=348.67K=348.67-273=75.67^oC$

Hence, the normal boiling point of ethanol will be, $348.67K$ or $75.67^oC$

3 0

2 years ago

In a car engine gasoline is burning to create mechanical energy which of the following statements is true? A. Some energy is los

Anvisha [2.4K]

Answer:

Some energy is lost as heat

Explanation:

It is correct to say that as the gasoline is converted to mechanical energy in the automobile engine, some of the energy is lost as heat.

Heat energy is on of the ways energy is lost in any system. The movement of mechanical parts and even the combustion of the gasoline produces heat energy.

These energy are usually lost to the environment.

4 0

2 years ago