2 years ago

Please help me experts answering these two questions!!!!

Mathematics

1 answer:

kondor19780726 [428]2 years ago

5 0

Answer:

7) 10cm

8) 4 feet

Step-by-step explanation:

formula for the volume of a cylinder is Πr2h (pie * square of radius * height)

You might be interested in

57.4 divided by 10???????

Gnesinka [82]

57.4/10=5.74
the answer is 5.74

6 0

2 years ago

Read 2 more answers

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

2 years ago

What is the area, in square inches, of the rectangle below?

chubhunter [2.5K]

The answer would be D i believe

6 0

1 year ago

The lengths of the sides of a triangle are represented by 3 consecutive even integers. if the perimeter of the triangle is 72 fe

iris [78.8K]

P = a + b + c
P = 72
a = x
b = x + 2
c = x + 4

72 = x + x + 2 + x + 4
72 = 3x + 6
72 - 6 = 3x
66 = 3x
66/3 = x
22 = x

x + 2 = 22 + 2 = 24
x + 4 = 22 + 4 = 26

the sides of ur triangle are : 22,24,26 <==

6 0

2 years ago

(2.4 x 10^-5)^4 Round to the nearest thousandth

lana66690 [7]

Answer:

Step-by-step explanation:

6 0

2 years ago

Please help me experts answering these two questions!!!!​

Please help me experts answering these two questions!!!!