Ask question

Ask question

All categories

2 years ago

11

Please help! If possible, please word your explanation simply.

2 answers:

Nesterboy [21]2 years ago

8 0

Answer: It is because if ∠N and ∠K are congruent and are same in size and shape.

Bond [772]2 years ago

8 0

Answer:

KLM is equal to NLM because in order to share a bisector, they have to have the same length. Also we can assume that <L and <M are the same since they share the same vertex, making both triangles equal.

Step-by-step explanation:

You might be interested in

11. Which of the following equations use the distributive property to multiply rational numbers?

Veronika [31]

Answer:

well you see there is go.ogle

8 0

2 years ago

Find the length of the third side. If necessary, round to the nearest<br> tenth.

WARRIOR [948]

B^2 = a^2 - c^2
b^2 = 9^2 - 5^2
b^2 = 56
b = 7.5

5 0

2 years ago

Can someone help me with my math problem pls my teacher is on my back about this

Karo-lina-s [1.5K]

Answer:

A: 8

B: 96

I'm not sure on C, sorry.

5 0

2 years ago

Read 2 more answers

At a pet store, 3/8 of the total animals were dogs. of those dogs 2/7 were labrador dogs. what fraction of the total pets were l

9966 [12]

Answer: 3/28

Step-by-step explanation:

Here we go, whenever you see the word "of" this mean to multiply

2/7 x 3/8 = 3/28

Answer: 3/28 .

I hope this help...

7 0

2 years ago

EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =

geniusboy [140]

The Lagrangian,

$L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)$

has critical points where its partial derivatives vanish:

$L_x=1-\lambda-2\mu x=0$

$L_y=2+\lambda-2\mu y=0$

$L_z=9-\lambda=0$

$L_\lambda=x-y+z-1=0$

$L_\mu=x^2+y^2-1=0$

$L_z=0$ tells us $\lambda=9$ , so that

$L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu$

$L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}$

Then with $L_\mu=0$ , we get

$x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2$

and $L_\lambda=0$ tells us

$x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}$

Then there are two critical points, $\left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right)$ . The critical point with the negative $x$ -coordinates gives the maximum value, $9+\sqrt{185}$ .

8 0

2 years ago