we know that
If a ordered pair (x,y) is a solution of the equation, then the ordered pair must satisfy the equation
we have the equation
Let's verify all the cases to determine the solution to the problem.
<u>case A)</u> point
Substitute the values of x and y in the equation
-------> is true
therefore
The point is a solution of the equation
<u>case B)</u> point
Substitute the values of x and y in the equation
-------> is true
therefore
The point is a solution of the equation
<u>case C)</u> point
Substitute the values of x and y in the equation
-------> is not true
therefore
The point is not a solution of the equation
<u>case D)</u> point
Substitute the values of x and y in the equation
-------> is not true
therefore
The point is not a solution of the equation
therefore
<u>the answer is </u>
Answer: If i'm correct i think the subsets of b are
={0},{1},{2},{0,1},{1,2} ,{2,0},{0,1,2},{phye}
Step-by-step explanation:
Answer:
please write complete question
Answer:
x(x+1)²
Step-by-step explanation:
x is a common factor to all terms so the first step is to factor it out:
... x(x² +2x +1)
The quadratic factor is recognizable as the square (x+1)², so the factoring is ...
... x(x +1)²