14). (Take π value as 22/7)
circumference = 66in
2πr = 66in
2×22/7×r = 66
r = 66×7/2×22
r = 21/2in
d = 2r => d = 2×21/2
therefore diameter of the circle = 21in
15). (Take π value as 3.14)
Circumference = 3.14m
2πr = 3.14m
2×3.14×r = 3.14
r = 3.14/3.14×2
r = 1/2m
Therefore the radius of the circle = 0.5m
16). (Take π value as 22/7)
Circumference = 33km
2πr = 33km
2×22/7×r = 33
r = 33×7/2×22
r = 21/4
d = 2r
d = 2×21/4
d = 21/2km
Therefore the diameter of the circle = 10.5km
A)Plugging in our initial statement values of y = 16 when x = 10, we get:
16 = 10k
Divide each side by 10 to solve for k:
16/10=
k = 1.6
Solve the second part of the variation equation:
Because we have found our relationship constant k = 1.6, we form our new variation equation:
y = 1.6x
Since we were given that x, we have
y = 1.6()
y = 0
B)Plugging in our initial statement values of y = 1 when x = 15, we get:
1 = 15k
Divide each side by 15 to solve for k:
1/15
=15k
k = 0.066666666666667
The period of the function is 2pi
Answer: 2/3
Step-by-step explanation: You take the 2 and divided it by 3 but your going to get a long decimal so you can put it into a fraction of 2/3
