Answer:
A) 5.2 x 10³ N
B) 8.8 x 10³ N
Explanation:
Part A)
= weight of the craft in downward direction = tension force in the cable when stationary = 7000 N
= Tension force in upward direction
= Drag force in upward direction = 1800 N
Force equation for the motion of craft is given as
- - = 0
7000 - 1800 - = 0
= 5200 N
= 5.2 x 10³ N
Part B)
= weight of the craft in downward direction = tension force in the cable when stationary = 7000 N
= Tension force in upward direction
= Drag force in downward direction = 1800 N
Force equation for the motion of craft is given as
- - = 0
- 7000 - 1800 = 0
= 8800 N
= 8.8 x 10³ N
Answer:
C
Explanation:
they both have to be the same for both to not move
A uniform thin solid door has height 2.20 m, width .870 m, and mass 23.0 kg. Find its moment of inertia for rotation on its hinges. Is any piece of data unnecessary? So far, I don't understand how to calculate moments of inertia for things like this at all. I can do a system of particles, but when it comes to any ridgid objects, such as this door or rods or cylinders, I don't get it. So basically I have no idea where to even start with this.
so A
Answer:
a) 25.5°(south of east)
b) 119 s
c) 238 m
Explanation:
solution:
we have river speed =2 m/s
velocity of motorboat relative to water is =4.2 m/s
so speed will be:
a) =+
solving graphically
=4.7 m/s
Ф=
=25.5°(south of east)
b) time to cross the river: t===119 s
c) d==(2)(119)=238 m
note :
pic is attached
Answer:
Van der Waal's equation
Explanation:
The Van der Waal's equation is use to calculate the properties of a gas under nonideal or real gases conditions.
.
Here P, V ,T ,n and R have usual meaning as in the ideal gas equation
that is PV=nRT
with the difference of constant a and b. a and b are constants representing magnitude of intermolecular attraction and excluded volume respectively respectively.