Answer:
or
Step-by-step explanation:
<u>Step 1: Cross Multiply</u>
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<u>Step 2: Divide both sides by 2.35</u>
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or
Answer: or
Answer:
a) 72.25sec
b) 6.25secs
c) after 10.5secs and 2 secs
Step-by-step explanation:
Given the height reached by the rocket expressed as;
s(t)= -4t^2 + 50t - 84
At maximum height, the velocity of the rocket is zero i.e ds/dt = 0
ds/dt = -8t + 50
0 = -8t + 50
8t = 50
t = 50/8
t = 6.25secs
Hence it will reach the maximum height after 6.25secs
To get the maximum height, you will substitute t - 6.25s into the given expression
s(t)= -4t^2 + 50t - 84
s(6.25) = -4(6.25)^2 + 50(6.25) - 84
s(6.25) = -156.25 + 312.5 - 84
s(6.25) = 72.25feet
Hence the maximum height reached by the rocket is 72.25feet
The rocket will reach the ground when s(t) = 0
Substitute into the expression
s(t)= -4t^2 + 50t - 84
0 = -4t^2 + 50t - 84
4t^2 - 50t + 84 = 0
2t^2 - 25t + 42 = 0
2t^2 - 4t - 21t + 42 = 0
2t(t-2)-21(t-2) = 0
(2t - 21) (t - 2) = 0
2t - 21 = 0 and t - 2 = 0
2t = 21 and t = 2
t = 10.5 and 2
Hence the time the rocket will reach the ground are after 10.5secs and 2 secs
Answer:
The transformation is (x,y) to (x-2,y-6)
Step-by-step explanation:
First of all, we note the coordinates of the point G
The coordinates of the point G is (2,6)
To bring this to the origin, we are looking at bringing it to the point (0,0)
To do this, we subtract 2 from the x-value and 6 from the y value
So what we have is that;
(x-2) and (y-6)
(x-2, y-6)
Is that 2/3 of q or 2 over 3q?
for 2/3 of q. q=1/2 x 3/2 =3/4=0.75
for 2 over 3q q = 2 x 2/3= 4/3=1.3333
Answer:4.3
You round to the tenths place