Answer:
The minimum sample size required is 207.
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population mean <em>μ</em> is:
The margin of error of this confidence interval is:
Given:
*Use a <em>z</em>-table for the critical value.
Compute the value of <em>n</em> as follows:
![MOE=z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\\3=2.576\times \frac{29}{\sqrt{n}} \\n=[\frac{2.576\times29}{3} ]^{2}\\=206.69\\\approx207](https://tex.z-dn.net/?f=MOE%3Dz_%7B%5Calpha%20%2F2%7D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C3%3D2.576%5Ctimes%20%5Cfrac%7B29%7D%7B%5Csqrt%7Bn%7D%7D%20%5C%5Cn%3D%5B%5Cfrac%7B2.576%5Ctimes29%7D%7B3%7D%20%5D%5E%7B2%7D%5C%5C%3D206.69%5C%5C%5Capprox207)
Thus, the minimum sample size required is 207.
Answer:
$0.67
Step-by-step explanation:
8.04=12x
<u>8.04</u>=<u>12x</u>
12. 12
.67=x
F(x) = x^2 - 6x + 4 {-3, 0, 5} (x, y) x is the domain, y is the range.
plug in the domain numbers into the equation to find the range.
y = x^2 - 6x + 4
y = -3^2 - 6(-3) + 4
y = 9 - (-18) + 4
y = 9 + 18 + 4
y = 31 (-3, 31)
y = x^2 - 6x + 4
y = 0^2 - 6(0) + 4
y = 0 - 0 + 4
y = 4 (0, 4)
y = x^2 - 6x + 4
y = 5^2 - 6(5) + 4
y = 25 - 30 + 4
y = -1 (5, -1)
c. {-1, 4, 31}
hope this helped, God bless!
Well I'm not sure what the answer would be since I'm not that smart but I did get the answer of 90, I did this by dividing 72 by 80 which equals .9 and I multiplied that by 100 and got 90.
