7y - 23 + 23x -16 + 8x - 21
31x + 7y - 60
What is the original problem equal to? You can't go any further unless you know.
Answer:
correct answers bc and d just did it
Step-by-step explanation:
The answer to this question is ....................................
The modified area is (1/48) (2πr(4h+3r))
<u>Step-by-step explanation:</u>
Let the radius be 'r' and height be 'h'.
Area of cylinder= 2π r(h+r)
The radius is shrunk down to quarter of its original radius
r = r/4
The height is reduced to a third of its original height
h = h/3
New Area = 2π(r/4) [(h/3) +(r/4) ]
= (1/4)2πr[(4h+3r) /12]
= (1/48) (2πr(4h+3r))
Answer:
(A)The area of the square is greater than the area of the rectangle.
(C)The value of x must be greater than 4
(E)The area of the rectangle is
Step-by-step explanation:
The Square has side lengths of (x - 2) units.
Area of the Square
The rectangle has a length of x units and a width of (x - 4) units.
Area of the Rectangle =
<u>The following statements are true:</u>
(A)The area of the square is greater than the area of the rectangle.
This is because the area of the square is an addition of 4 to the area of the rectangle.
(C)The value of x must be greater than 4
If x is less than or equal to 4, the area of the rectangle will be negative or zero.
(E)The area of the rectangle is