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2 years ago

What is the first time at which the kinetic energy is twice the potential energy?

Physics

1 answer:

Pavlova-9 [17]2 years ago

5 0

Answer:

When the tangent of the cyclic frequency and time will be equal √2

Explanation:

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A sky diver, with parachute unopened, falls 625 m in 15.0 s. Then she opens her parachute and falls another 362 m in 139 s. What

Jobisdone [24]

Answer:

$v_{avg} = 6.41 m/s$

Explanation:

Average velocity is defined as the ratio of total displacement of the motion and total time taken in that motion

here we know that initially the sky diver drops without opening parachute by total displacement 625 m

then she open her parachute and drop another 362 m

so first it took time t = 15 s to drop without open parachute

then it took t = 139 s to drop next displacement

so here total displacement is given as

$d = 625 m + 362 m$

total time is given as

$t = 15 s + 139 s$

so average velocity is given as

$v_{avg} = \frac{625 + 362}{15 + 139}$

$v_{avg} = 6.41 m/s$

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2 years ago

You ran a power plant what could you do to make this generator produce electricity

DIA [1.3K]

You could use a magnetic generator or you could use hydraulic power

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2 years ago

In an experiment in space, one proton is held fixed and another proton is released from rest a distance of 1.00 mm away. part a

mihalych1998 [28]

<span>We can use Coulomb's law to find the force F acting on the proton that is released. F = k x Q1 x Q2 / r^2 k = 9 x 10^9 Q1 is the charge on one proton which is 1.6 x 10^{-19} C Q2 is the same charge on the other proton r is the distance between the protons F = (9x10^9) x (1.6 x 10^{-19} C) x (1.6 x 10^{-19} C) / (10^{-3})^2 F = 2.304 x 10^{-22} N We can use the force to find the acceleration. F = ma a = F / m a = (2.304 x 10^{-22} N) / (1.67 x 10^{-27} kg) a = 1.38 x 10^5 m/s^2 The initial acceleration of the proton is 1.38 x 10^5 m/s^2</span>

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2 years ago

Suppose that a star has a spectrum that includes red, blue, and violet lines spaced in the pattern of the lines from hydrogen bu

ladessa [460]

Answer:

It can be concluded that the star is moving away from the observer.

Explanation:

Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect).

The wavelength at rest for this case is 434 nm and 410 nm ( $\lambda_{0} = 434nm$ , $\lambda_{0} = 410nm$ )

$Redshift: \lambda_{measured} > \lambda_{0}$

$Blueshift: \lambda_{measured} < \lambda_{0}$

Since, $\lambda_{measured}$ (444nm) is greater than $\lambda_{0}$ (434 nm) and $\lambda_{measured}$ (420nm) is greater than $\lambda_{0}$ (410 nm), it can be concluded that the star is moving away from the observer

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2 years ago

Why does it take double the applied force to move a mass double the size?

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56-999999999999999999999-4 is the best for my mom

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2 years ago