Answer:
the plane's current height above the ocean is 3.42 miles
Step-by-step explanation:
Given that the diagonal distance between the plane and the aircraft carrier is 10 miles.
What we need to find is the vertical distance between the plane and the aircraft carrier which is the plane's current height above the ocean. This can be gotten using sine rule.
For sine rule, you need a side and its opposite angle. For this question the triangle formed is a right angle triangle with diagonal distance, vertical distance and horizontal distance.
let a = diagonal distance = 10 miles
let the opposite angle to the diagonal distance be A = 90° (right angle)
let the vertical distance = b
let the opposite angle to the vertical distance be B = 20°
Sine rule states that
∴
⇒ b = 3.42 miles
Therefore the plane's current height above the ocean is 3.42 miles
Sure ... exactly the way you simplify "2 + 2" when it comes up in conversation ... perform the indicated operation wherever possible. In simplified form, -4x-x is written as. " -5x ".
To find the zeros of this function, we must first set the entire function equal to 0
f(x) = x² - 2x - 15 = 0
Since this is a quadratic function, we must use the quadratic formula, which is:
Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15
Now let's plug those in:
which simplifies to:
Simplified further:
And divide it by the 2 on the bottom gives us:
2+4 = 6
2-4 = -2
So the zeros of this function are
-2 and
6
Answer:
I think it's C) 18.5ft^2
it's just an educated guess though I haven't worked on area in a while
Answer:
its A
Step-by-step explanation:
not gonna explain it cause I dont have to ._. plus it wasnt that hard