Here if we assume that there is no air friction on both balls then we can say
now the acceleration is given as
so here both the balls will have same acceleration irrespective of size and mass
so we can say that to find out the time of fall of ball we can use
now from above equation we can say that time taken to hit the ground will be same for both balls and it is irrespective of its mass and size
Answer:
because the gravitational pull is maximum at the poles and decreases as it comes down toward the equator.
Answer:true,because velocity is directly proportional to speed or velocity
Explanation:
Velocity = frequency x wavelength
The velocity or speed varies directly with the frequency, so as the frequency is increased, the velocity or speed is also increased
<span>141.6 million mi,and idk what u mean by how</span>
Complete Question
A gas gun uses high pressure gas tp accelerate projectile through the gun barrel.
If the acceleration of the projective is : a = c/s m/s2
Where c is a constant that depends on the initial gas pressure behind the projectile. The initial position of the projectile is s= 1.5m and the projectile is initially at rest. The projectile accelerates until it reaches the end of the barrel at s=3m. What is the value of the constant c such that the projectile leaves the barrel with velocity of 200m/s?
Answer:
The value of the constant is
Explanation:
From the question we are told that
The acceleration is
The initial position of the projectile is s= 1.5m
The final position of the projectile is
The velocity is
Generally
and acceleration is
so
=>
integrating both sides
Now for the limit
a = 200 m/s
b = 0 m/s
c = s= 3 m
d == 1.5 m
So we have
=>