Answer:
Water (H₂O) is the missing product
Explanation:
Let's write the equation involved:
H₃C₆H₅O₇(aq) + 3NaHCO₃(aq) ---->
When we watch the first product which is Na₃C₆H₅O₇, we can see that in this case, there was a displacement of the H₃ by the atoms of Na. This give us an idea of what kind of reaction is ocurring. If we follow the principle of the displacement, the reaction should be the following:
H₃C₆H₅O₇(aq) + 3NaHCO₃(aq) ----> Na₃C₆H₅O₇(aq) + 3H₂CO₃(aq)
However, this last compound (H₂CO₃) is very unstable in the presence of sodium citrate, so, the acid suffers another internal reaction:
H₂CO₃(aq) -------> CO₂(g) + H₂O(l)
The CO₂ are the bubbles produced, and the water is produced in solution. Therefore, the products of the general reaction is:
H₃C₆H₅O₇(aq) + 3NaHCO₃(aq) ----> Na₃C₆H₅O₇(aq) + 3CO₂(g) + 3H₂O(l)