-5(6p+1)=-25-5p+20-25p

In a batch of 440 water purifiers, 8 were found to be defective. What is the probability that a water purifier chosen at random

LiRa [457]

Answer:

1.8% or 1.818181%

Step-by-step explanation:

If in a batch of 440 water purifiers, we find 8 to be defective.

Then the probability of the next purifier being defective is 8/440

In percentage = 8/440 * 100

=> 8/44 * 10

=> 8/22 * 5

=> 40/22

=> 20 / 11

20/11 is roughly 1.8181818

Rounding it to the nearest tenth, we get 1.8%

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

3 0

2 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in slope-intercept formula, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of k and m.

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

1 year ago

during one month the orangevale parks and recreation district spent $5720 for various activities. they spent $1430 on mommy and

AysviL [449]

To solve this problem, we must figure out what percent of the total spending was spent on mommy and baby exercise programs. To figure this out, we should divide how much was spent on the mommy and baby exercise by the total amount spent on the district activities.

$1430/$5720 = 0.25

This is a percentage, or a portion out of 100, which means we must multiply this decimal by 100 to find its equivalent percentage.

0.25 * 100 = 25

Therefore, your answer is 25% of the total spending was spent on mommy and baby exercise programs.

Hope this helps!

5 0

2 years ago

G^4+ 5h when g=2 & h=4

il63 [147K]

Answer: 36

Step-by-step explanation:

g^4+5h

2^4+5(4)

16+20

36

7 0

2 years ago

I need help with 8 9 thanks

sasho [114]

#8: $900. (I found this answer by multiplying 3000 and 0.3 by the way)
#9: 160 miles. I found this answer by multiplying 80 by two, since two halves/50% make a whole or 100%.

3 0

2 years ago