The answer is -4/7 or in decimal it’s -0571429
Answer:
The probability of selecting a sample which doesn't capture the true value of μ would be 10% rather than 5% if they decide to calculate a 90% confidence interval rather than a 95% confidence interval from the sample they will select.
Step-by-step explanation:
The correct answer is the last statement, but first, let's look at the other statements:
<em>Their confidence interval would be less likely to capture the </em><em>sample </em><em>mean.</em>
This statement is not correct because the <em>confidence </em>of a confidence interval gives us the probability of capturing the true value of the population mean.
<em>They would </em><em>decrease </em><em>the margin of error of their confidence interval if they calculated a 90% rather than a 95% confidence interval.</em>
If we want more confidence we must establish more precision, which means more error. In other words if the confidence increases so does the error for a fixed sample size. The second statement is false.
<em>The probability of selecting a sample which doesn't capture the true value of μ would be 10% rather than 5% if they decide to calculate a 90% confidence interval rather than a 95% confidence interval from the sample they will select.</em>
As stated before the <em>confidence </em>of a confidence interval is the probability that the interval contains the true value of μ. Therefore, if we increase the confidence from 95% to 90% then this probability also increases. A 90% confidence means that there's a 10% probability of not containing the true mean. Likely, a 95% confidence means that there's a 5% probability of not containig the true mean. The third statement is true.
The answer is B. Anxiety disorder
Multiply it by 4 then it would taste the same as the one batch
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(x-25) = 7 multiply 5 to both sides first
-(x-25) = 35 then expand the brackets
-x+25=35 make x the subject now;
-x=10
x= -10