From tables, the density of mercury is
13545 kg/m^3 at 20°C,
13472 kg/m^3 at 50°C.
Because mass = density * volume, the mass of mercury at 20°C is
m = (13545 kg/m^3)*(0.002 m^3) = 27.09 kg
Let V = volume of mercury at 50°C.
Because the mass of mercury does not change, therefore at 50°C,
(13472 kg/m^3)*(V m^3) = 27.09
V = 27.09/13472 = 0.0020108 m^3
Answer: B. 0.002010812 m³
Answer:
0.0567 N
Explanation:
q1 = 3 micro coulomb
q2 = - 2 micro coulomb
OB = 50 cm
AB = 60 cm
By using Pythagoras theorem in triangle OAB
OA = 78.1 cm
By using the Coulomb's law, the force on 3 micro coulomb due to -2 micro coulomb is
F = 0.0885 N
The horizontal component of force is
= F CosФ =
= 0.0885 x 50 / 78.1 = 0.0567 N
Answer:
A.) acceleration= 55.6m/s^2
B.) acceleration of table= 5.0m/s^2
C.) More acceleration
Explanation:
A.) 100N/1.8kg= -55.6
B.) 100N÷20kg= 5
C.) Because since the table would have less mass, it would have had to accelerate more