<h2>Answer </h2>
The kinetic energy is 8100 J.
<u>Explanation</u>
Mass is 50.0kg and velocity is 18 m/s, the kinetic energy is:
As we know the formula of kinetic energy which is K.E = ½ ( mv ^ 2 ),
mass = m = 50.0kg
velocity = v = 18 m / s,
by putting values in the formula,
K.E = ½ ( mv ^ 2 ),
K.E = ½ ( 50kg ) . ( 18 m / s ) ^ 2
K.E = ½ ( 50kg ) . ( 324 ),
=> K.E = 1/2 ( 16200 ),
=> K.E = 16200 / 2,
=> K.E = 8100J.
Hence, the kinetic energy ( K.E ) is 8100 joule ( J ).
Answer:
um, when you talk with other people about stuff. (I'm not trying to sound like a smarta s s I'm just giving a definition...)
Explanation:
Answer:
a) v₃ = 19.54 km, b) 70.2º north-west
Explanation:
This is a vector exercise, the best way to solve it is finding the components of each vector and doing the addition
vector 1 moves 26 km northeast
let's use trigonometry to find its components
cos 45 = x₁ / V₁
sin 45 = y₁ / V₁
x₁ = v₁ cos 45
y₁ = v₁ sin 45
x₁ = 26 cos 45
y₁ = 26 sin 45
x₁ = 18.38 km
y₁ = 18.38 km
Vector 2 moves 45 km north
y₂ = 45 km
Unknown 3 vector
x3 =?
y3 =?
Vector Resulting 70 km north of the starting point
R_y = 70 km
we make the sum on each axis
X axis
Rₓ = x₁ + x₃
x₃ = Rₓ -x₁
x₃ = 0 - 18.38
x₃ = -18.38 km
Y Axis
R_y = y₁ + y₂ + y₃
y₃ = R_y - y₁ -y₂
y₃ = 70 -18.38 - 45
y₃ = 6.62 km
the vector of the third leg of the journey is
v₃ = (-18.38 i ^ +6.62 j^ ) km
let's use the Pythagorean theorem to find the length
v₃ = √ (18.38² + 6.62²)
v₃ = 19.54 km
to find the angle let's use trigonometry
tan θ = y₃ / x₃
θ = tan⁻¹ (y₃ / x₃)
θ = tan⁻¹ (6.62 / (- 18.38))
θ = -19.8º
with respect to the x axis, if we measure this angle from the positive side of the x axis it is
θ’= 180 -19.8
θ’= 160.19º
I mean the address is
θ’’ = 90-19.8
θ = 70.2º
70.2º north-west
Answer:
1. telescope
2.
f- focal length
f- focal length r- the radius of curvature of the mirror
p-the distance of the object from the vertex of the mirror
l-the distance of the figure from the vertex of the mirror
2) they add the insulation to better the durability or the earbuds
