Find an equation of the line that is perpendicular to the graph of 2x+5y=5 and contains the point of intersection of the graphs
of y=x+4 and y–2x=5.
1 answer:
Answer:
5(x+1) -2(y-3) = 0
Step-by-step explanation:
For a given line ax+by=c and point (h, k), a perpendicular line through the point can be written as ...
b(x-h) -a(y-k) = 0
A graphing calculator shows the point of intersection of the graphs of the two lines to be (x, y) = (-1, 3), so the line perpendicular to 2x+5y=5 through that point can be written ...
5(x+1) -2(y-3) = 0
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In the attached graph, the requested line is shown in black.
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The vertex form:
The axis of symetry is x = h.
We have
Substitute: