There are 64 people in the room.
Since the ratio for women increases 1 when 8 women enter the room, for every time there is 1 in the ratio there are 8 people. That means that originally you have to do 3x8 and 4x8. You get 24 and 32 which equals 56. Then when 8 more women enter the room, you get 64.
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
<u>Answer</u>:
c = 9
<u>Explanation</u>:
given: f(x)=3x-7
<em>if f(c) =20</em>
To solve this replace x with c and then y is 20.
<u>Solve</u>:
3c - 7 = 20
3c = 27
c = 27 ÷ 3
c = 9
Answer:
In the 3rd and 4th quadrants of the coordinate system
ie π < θ < 2π. At π and 2π the sine values are zero
Step-by-step explanation:
