Answer:
First, find tan A and tan B.
cosA=35 --> sin2A=1−925=1625 --> cosA=±45
cosA=45 because A is in Quadrant I
tanA=sinAcosA=(45)(53)=43.
sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.
sinB=1213 because B is in Quadrant I
tanB=sinBcosB=(513)(1312)=512
Apply the trig identity:
tan(A−B)=tanA−tanB1−tanA.tanB
tanA−tanB=43−512=1112
(1−tanA.tanB)=1−2036=1636=49
tan(A−B)=(1112)(94)=3316
kamina op bolte
✌ ✌ ✌ ✌
Answer:
2.44pi
Step-by-step explanation:
it's in the picture
Answer: m=1
Step-by-step explanation:
Use the equation y=y2-y1 over x2-x1
1. label your points
0=x1
-2=y1
-3=x2
-5=y2
The first pair is x1 and y1 and the next pair is x2 and y2
plug in the numbers to find your answer
Answer:
4,9
Step-by-step explanation:
(1). 4,9 are not prime number
(2) 4=1×2×2
9 = 1×3×3
so,
HCF of 4,9 will be
= 1.