In this problem it
states that one tenth or only 10% is Canada’s population to the United States.
Hence with the steps we
can identify the population of the United States.
<span><span>1.
</span>10 %
= 32 million or 0.1 = 32 million</span>
<span><span>2.
</span>Then 32
million / 0.1 = 320, 000, 000 million</span>
Therefore there are 320,
000, 000 million living in the United States
Adding one zero. Why the zeroes? It is
the result because of the power of 10 in a hundred percent population coming
from the Canada’s population. Take note that 100% = 320, 000, 000 million of
the USA while 10% of it is Canada so we divide it by 0.1 which is 32, 000, 000
(the power of ten)
The frequency for this problem would me x2 every time you add on to the chart or go down the chart good luck:)
I need more information to answer this
So right now you see that you have x and y intercept right? Then plug those intercepts in equation that you have and solve for z. Which means z=5(1)(1) will be 5, 5(4)(1) will be 20, and 5(1)(2) will be 10. So, overall you have 5, 20, 10.
Answer: P(odd) = 0.499
Step-by-step explanation:
Given:
Total number of people = 20
Number of men = 12
Number of women = 8
Number of jury to be selected = 6
For the jury to have an odd number of women. it must have either of the three.
1. 1 woman , 5 men
2. 3 women, 3 men
3. 5 women, 1 man
The total possible ways of selecting the 6 people jury is;
N = 20C6 = 20!/6!(20-6)!
N = 38760
The possible ways of selecting;
Case 1 : 1 woman, 5 men
N1 = 8C1 × 12C5
N1 = 8 × 792 = 6336
Case 2 : 3 women , 3 men
N2 = 8C3 × 12C3
N2 = 12320
Case 3 : 5 women, 1 man
N3 = 8C5 × 12C1
N3 = 672
P(Odd) = (N1+N2+N3)/N
P(odd) = (6336+12320+672)/38760
P(odd) = 19328/38760
P(odd) = 0.499
