Answer:
x^2 + y^2 + 16x + 6y + 9 = 0
Step-by-step explanation:
Using the formula for equation of a circle
(x - a)^2 + (y + b)^2 = r^2
(a, b) - the center
r - radius of the circle
Inserting the values given in the question
(-8,3) and r = 8
a - -8
b - 3
r - 8
[ x -(-8)]^2 + (y+3)^2 = 8^2
(x + 8)^2 + (y + 3)^2 = 8^2
Solving the brackets
( x + 8)(x + 8) + (y +3)(y+3) = 64
x^2 + 16x + 64 + y^2 + 6y + 9 = 64
Rearranging algebrally,.
x^2 + y^2 + 16x + 6y + 9+64 - 64 = 0
Bringing in 64, thereby changing the + sign to -
Therefore, the equation of the circle =
x^2 + y^2 + 16x + 6y + 9 = 0
Answer:
3
Step-by-step explanation:
i would say 3 different ways because 4 x 3 = 12
Hope this helps!
28.4
Explanation
(Multiply the numbers) 3.24 x 10= 32.4
(Subtract the numbers) 32.4 - 4= 28.4
I thinks 5 because -2(x) = -2x and -2(5)=-10
So -2x=-10
-10/-2=5
X=5
Answer:
B and D
Step-by-step explanation:
plug in the x and y for the x and y in the equation
if the two sides come out equal to eachother they satify the function
if they dont well they dont satisfy the function
hope this helps <3