For the answer to the question above, use these formulas in solving your problem and as a guide.
<span>
MM = 342 (g/mol) </span>
<span>171 (g) / 342(g/mol) = x mol of sucrose </span>
<span>x moles of sucrose/ 1.25 L = Molarity of soultion
</span>I hope I helped you with your problem. Have a beautiful day!
Your Question: {How many objects are in a mole?}
Helpful Knowledge: (We Know the amount in an object: 12g or C^12)
{A number of objects that are in a mole of objects?}
Well for the question it is pretty easy to answer because a number of objects in One mole would equal 6.02 × 10²³
Which 6.02 × 10²³ is an Avogadro's Number.
So it depends on how many objects you have.
So for every object you have, One mole would equal 6.02 × 10²³. Or 62,000,000,000,000,0000,000,000. Big Number am I right. So that's why we just use 6.02 × 10²³.
Anywho, your answer would be 6.02 x 10²³ x n.
N would equal the number of objects you're calculating.
Final Answer: 6.02 x 10²³ x (n) = (Your Answer)
Hope this helps! Have a great day. If you need anything else, feel free to hope right in my inbox. Or comment below. ↓
Stoichiometry time! Remember to look at the equation for your molar ratios in other problems.
31.75 g Cu | 1 mol Cu | 2 mol Ag | 107.9 g Ag 6851.65
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ → ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ = 107.9 g Ag
∅ | 63.5 g Cu | 1 mol Cu | 1 mol Ag 63.5
There's also a shorter way to do this: Notice the molar ratio from Cu to Ag, which is 1:2. When you plug in 31.75 into your molar mass for Cu, it equals 1/2 mol. That also means that you have 1 mol Ag because of the ratio, qhich you can then plug into your molar mass, getting 107.9 as well.
Answer:
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Answer:
The formation of a meander. As the river erodes laterally, to the right side then the left side, it forms large bends, and then horseshoe-like loops called meanders . The formation of meanders is due to both deposition and erosion and meanders gradually migrate downstream.
