Only Table 2 shows direct variation. Every y value is 7 times the associated x value.
2
2x
2
+5x−12
1 Split the second term in
2
x
2
+
5
x
−
1
2
2x
2
+5x−12 into two terms.
2
x
2
+
8
x
−
3
x
−
1
2
2x
2
+8x−3x−12
2 Factor out common terms in the first two terms, then in the last two terms.
2
x
(
x
+
4
)
−
3
(
x
+
4
)
2x(x+4)−3(x+4)
3 Factor out the common term
x
+
4
x+4.
(
x
+
4
)
(
2
x
−
3
)
(x+4)(2x−3)
Infinitely many, but they will all be proportional to each other