Answer:
The half-life of the radioactive substance is 135.9 hours.
Step-by-step explanation:
The rate of decay is proportional to the amount of the substance present at time t
This means that the amount of the substance can be modeled by the following differential equation:
Which has the following solution:
In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.
After 6 hours the mass had decreased by 3%.
This means that . We use this to find r.
So
Determine the half-life of the radioactive substance.
This is t for which Q(t) = 0.5Q(0). So
The half-life of the radioactive substance is 135.9 hours.
Okay so you're trying to find the unit rate of 720yds/4min. If you divide 720 by 4 you will have the unit rate as 180yds/1 min or 60 sec then if you divide 180 and 60 by 4 again you will get the answer of 45yds/15sec.
8-5=3
3-5=-2
-2-5=-7
So the rule is -5 or subtract 5
Answer:
missing angle <60 and side lengths 5, 5
Step-by-step explanation:
we understand from the given information that the triangle in question is a special right triangle
and since this is a special triangle the side lengths follows :
the side length that sees <90 is represented by 2x
the side length that sees <60 is represented by x
and the side length that sees <30 is represented by x
2x = 10 so x = 5 and x = 5