Answer:
Step-by-step explanation:
Number of Men, n(M)=24
Number of Women, n(W)=3
Total Sample, n(S)=24+3=27
Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>
(a)Probability that both appointees are men.
(b)Probability that one man and one woman are appointed.
To find the probability that one man and one woman are appointed, this could happen in two ways.
- A man is appointed first and a woman is appointed next.
- A woman is appointed first and a man is appointed next.
P(One man and one woman are appointed)
(c)Probability that at least one woman is appointed.
The probability that at least one woman is appointed can occur in three ways.
- A man is appointed first and a woman is appointed next.
- A woman is appointed first and a man is appointed next.
- Two women are appointed
P(at least one woman is appointed)
In Part B, 
Therefore:
Answer:
Step-by-step explanation:
Here you go mate
PEDMAS
STEP 1
3<-2x-137 equation
STEP 2
3<-2x-137 simplify by reversing equation
-2x-137>3
STEP 3
-2x-137>3 simplify
-2x>140
step 4
-2x>140 look for a number that can divide the two numbers like 2
-2x
/-2
>
140
/-2
1>-70
answer
x>-70
Answer: 
, where x= width of the rectangle ( in inches).
Step-by-step explanation:
Let x= width of the rectangle ( in inches).
Then its length = 2x-7 ( in inches).
Area of rectangle = Length × width
= (2x-7) × (x)
= 2x × x -7 ×x
= 2x²-7x
The area of the rectangle is 72 square inches.
Hence, the equation that represents the given situation :
Grade In Favor Opposed Undecided Total
9 4 2 8 14
10 7 11 8 26
11 14 15 9 38
12 11 5 10 26
Total 36 33 35 104
Above is a partial sum chart that will help us in our quest.
P(Grade 9 | opposed)
The probability of Grade 9, given opposed, is the portion of opposed students that are in grade 9.
Total number opposed: 33
Number opposed in Grade 9: 2
P(Grade 9 | opposed) = 2 / 33 = 0.06
P(opposed | Grade 9)
Total Number Grade 9: 14
Number opposed in Grade 9: 2
P(opposed | Grade 9) = 2 / 14 = 0.14
8 appears in the 10 thousand's place and is of 80,000 in value.
