Answer:
Moles of carbon dioxide are 1.57
Explanation:
Using ideal gas law, you can find moles of a gas with its pressure, temperature and volume, thus:
PV = nRT
PV/RT = n
<em>Where P is pressure, V is volume (35.2L); R is gas constant (0.082atmL/molK); T is absolute temperature and n are moles</em>
At STP, temperature is 273.15K and pressure is 1atm
Replacing:
1atm×35.2L / 0.082atmL/molK×273.15K = n
<em>1.57 = n</em>
<em>Moles of carbon dioxide are 1.57</em>
Answer:
One tablet can neutralize 150 mL of stomach acid at a pH of 1.0
Explanation:
Step 1: Data given
Mass of calcium carbonate = 750 mg = 0.75 grams
Molar mass of CaCO3 = 100 g/mol
pH = 1.0
Step 2: The balanced equation
2HCl + CaCO3 → CaCl2 + H2CO3
Step 3: Calculate molarity of HCl
pH = -log[H+] = 1
[H+] = 0.1 M = 0.10 mol/L
Step 4: Calculate moles of CaCO3
Moles CaCO3 = 0.75 grams / 100g/mol
Moles CaCO3 = 0.0075 mol
Step 5: Calculate moles of HCl
For 2 moles HCl we need 1 mol CaCO3 to produce CaCl2 and 1 mole of H2CO3
For 0.0075 moles of CaCO3 we have 2*0.0075 = 0.015 moles HCl
Step 6: Calculate volume of HCl
Volume = moles /molarity
Volume = 0.015 moles / 0.1 M
Volume = 0.15 L = 150 mL
One tablet can neutralize 150 mL of stomach acid at a pH of 1.0.
Answer:
<h2>100°C is the boiling point of water in degrees Celsius</h2>
Answer:
3 > 2> 1
Explanation:
Aromatic compounds undergo electrophilic substitution reaction with several electrophiles.
Some substituted benzenes are more reactive towards electrophilic aromatic substitution than unsubstituted benzene.
Certain groups of substituents increase the ease with which an aromatic compound undergoes aromatic substitution.
If we look at the compounds closely, we will notice that only toluene leads to easy reaction with CH3Cl / AlCl3. Thus is due to the +I inductive effect of -CH3 which stabilizes the negatively charged intermediate produced in the reaction.
Here we have to draw the four isomers of the compound 3-bromo-4-fluorohexane.
The four isomers of the compound is shown in the figure.
In an organic molecule the chiral -C center is that where four (4) different groups are present. In 3-bromo-4-fluorohexane the 3 and 4 positions are chiral centers. The possible isomers of a molecule can be obtained from the formula 2n. As here 2 chiral centers are present thus number of stereoisomers will be 2×2 = 4.
The four different isomers as shown in the figure are 3R-, 4R-; 3S-, 4S; 3R, 4S and 3S-, 4R- 3-bromo-4-fluorohexane.
In the 3-bromo-4-fluorohexane the functional groups are -Br, C₂H₅, -C₃H₆F and -H for 3-position and -F, -C₂H₅, -C₃H₆ and -H for 4-position respectively.
The priority of the -3 position will be Br > C₃H₆F > C₂H₅ > H and for -4 position F > C₃H₆Br > C₂H₅ > H. If the rotation from the higher priority group to lower is clockwise and anticlockwise then the S- and R- notation are used respectively. However if the -H atom is present at the horizontal position then the notation will be reverse.
Thus the four isomers of the compound is shown.