De broglie wavelength, , where h is the Planck's constant, m is the mass and v is the velocity.
Mass of hydrogen atom,
v = 440 m/s
Substituting
Wavelength
So the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm
Answer:
The equation of D = m/V
Where D = density
m = mass
and V = volume
We are solving for V, so with the manipulation of variables we multiply V on both sides giving us
V(D) = m
now we divide D on both sides giving us
V = m/D
We know our mass which is 600g and our density is 3.00 g/cm^3
so
V = 600g/3.00g/cm^3 = 200cm^3 or 200mL
a cubic centimeter (cm^3) is one of the units for volume. It's exactly like mL. 1 cm^3 = 1 mL
If you wish to change it to L, you'd have to convert
Explanation:
Answer:
2.27kg
Explanation:
The Potential energy gained = Force gravity× Height
Force gravity on the ball is GPE/ height
56.8/2.5=22.72N
the mass = 22.72/10= 2.27kg