Answer:
1/1560
Step-by-step explanation:
The chance of you winning is 1/40, since there are 40 students and you are one of those students. Since, you cannot win again once you win once, you are eliminated. This leaves us with 39 people left. The chances of your friend being chosen out of the 39 people left is 1/39. Now you must multiply 1/40 and 1/39. After multiplying, you get 1/1560.
12%
$68 - 59.9 = $8.1
$8.1/$68 = 0.11911764705
0.11911764705 x100 = 11.911764705
11.911764705 is rounded up to 12
12%
Answer:
Step-by-step explanation:
A parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. The length of Jk can be either 10 or 26.
<h3>What is a rectangle?</h3>
A parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. A rectangle is always a parallelogram and a quadrilateral but the reverse statement may or may not be true.
Since in a rectangle the opposite sides are equal, therefore, the sides NM and JK will be equal.
JK = MN
8x - 14 = x² + 1
0 = x² - 8x + 15
x = 5, 3
Hence, the length of Jk can be either 10 or 26.
The complete questions are:
Quadrilateral JKMN is a rectangle, if NM= 8x - 14 and JK= x squared + 1, find JK.
Learn more about Rectangle:
brainly.com/question/15019502
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y=x+14 line 1
y=3x+2 line 2
These are both the equation of lines written in slope intercept form
y=mx+b where m is the slope and the point (0,b) is the y intercept.
The first line has a slope of m=1. The 2nd line has a slope of m=3
Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.
We already have y solved in terms of x from either equation so we can use substitution to solve the system.
Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.
x+14=3x+2
solve for x.
Subtract x from both sides...
14= 3x-x+2
14=2x+2
subtract 2 from both sides
14-2=2x
12=2x
divide both sides by 2
6=x
We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.
y=6+14
y=20
These two lines cross at the point (6,20) which is a point the two lines have in common.
Hope I helped (SharkieOwO)
