First, calculate the number of moles of sodium present with the given mass,
31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium
It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.
mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
mols of H2 = 0.685 mols H2
Then, at STP, 1 mol of gas = 22.4 L.
volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
volume of H2 = 15.34 L
Answer: 15.34 L
Answer:
Explanation:
Step 1. Calculate the pOH
pOH =-log[OH⁻]
pOH =-log(1.0 × 10⁻⁹)
pOH = 9.00
Step 2. Calculate the pH
pH + pOH = 14.00
pH + 9.00 = 14.00
The compound that has the element ratio 2:1 is 2H20.
In 2H2O, four atoms of hydrogen react with two hydrogen of oxygen to form molecules of water. Four divided by two will give two, that implies ratio 2;1. This implies that, two atoms of hydrogen will react with one atom of oxygen to give a molecule of water.<span />
Answer
The volume of the container that the gas is in = 874.30 L
Explanation
Given:
Moles, n = 3.2 mol
Pressure, P = 0.095 atm
Temperature, T = 43 °C = (43 + 273.15 K) = 316.15 K
Molar gas constant, R = 0.0821 atm•L/mol•K
What to find:
The volume of the container that the gas occupied.
Step-by-step solution:
The volume of the container that the gas occupied can be calculated using the ideal gas equation.
Therefore, the volume of the container that the gas occupied is 874.30 L