REPOST IT A BIT CLEARER sorry i was on caps and im to lazy to elete what i wworte and repost it
Answer:
(5.4582 ; 6.8618)
Step-by-step explanation:
Given the data:
6 10 2 6 3 3 3 6 6 6 6 5 8 9 10 10 7 9 3 6 5 10 9 9 10 3 8 6 6 3 3 6 6 5 4 10 9 3 5 7 10 6 3 8 6 8 3 3 5 5
Sample mean, xbar = Σx / n
n = sample size = 50
ΣX = 308
xbar = 308 / 50 = 6.16
Using a Calculator :
The sample standard deviation, s = 2.469
Confidence interval = xbar ± margin of error
Margin of Error = Tcritical * s/sqrt(n)
Tcritical at 95% ; df = 50 - 1 = 49
Tcritical = 2.010
Hence,
Margin of Error= 2.010 * (2.469/sqrt(50)) = 0.7018
Lower boundary : (6.16 - 0.7018) = 5.4582
Upper boundary : (6.16 + 0.7018) = 6.8618
(5.4582 ; 6.8618)
Answer:
-7/3
Step-by-step explanation:
2(6−4)=3(6+2)
2(6x-4)=3(6x+2)
Solve
1
Distribute
2(6−4)=3(6+2)
{\color{#c92786}{2(6x-4)}}=3(6x+2)
12−8=3(6+2)
{\color{#c92786}{12x-8}}=3(6x+2)
2
Distribute
12−8=3(6+2)
12x-8={\color{#c92786}{3(6x+2)}}
12−8=18+6
12x-8={\color{#c92786}{18x+6}}
3
Add
8
8
to both sides of the equation
12−8=18+6
12x-8=18x+6
12−8+8=18+6+8
12x-8+{\color{#c92786}{8}}=18x+6+{\color{#c92786}{8}}
5 more steps
Solution
=−7/3
Answer:
Step-by-step explanation:
c its the closes
Answer:
Step-by-step explanation:
*Notes (clarified by the person who asked this question):
-The triangle on the right has a right angle (angle that appears to be a right angle is a right angle)
-The bottom side of the right triangle is marked with a question mark (?)
<u>Triangle 1 (triangle on left):</u>
Special triangles:
In all 45-45-90 triangles, the ratio of the sides is 
, where 
is the hypotenuse of the triangle. Since one of the legs is marked as 
, the hypotenuse must be 
It's also possible to use a variety of trigonometry to solve this problem. Basic trig for right triangles is applicable and may be the simplest:
<u>Triangle 2 (triangle on right):</u>
We can use basic trig for right triangles to set up the following equations:
,
We can verify these answers using the Pythagorean theorem. The Pythagorean theorem states that in all right triangles, the following must be true:
, where 
is the hypotenuse of the triangle and 
and 
are two legs of the triangle.
Verify 
