An airplane at T(80,20)needs to fly to both U(20,60) and V(110,85). what is the shortest possible distance for the trip?
1 answer:
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Answer:
42°
Step-by-step explanation:
3x + 54° = 180° [Supplementary angles]
=> 3x = 180 - 54
=> 3x = 126
=> <u>x = 42</u><u>°</u><u> </u><u>(Ans)</u>