The correct answer is C. Colligative properties only depend upon the number of solute particles in a solution but not on the identity or nature of the solute and solvent particles. I hope this anwers your question.
'The Sedimentary rock formed from years of sediments piling on top of it and being compressed.'
Answer:
0.000000540
Explanation:
Step 1: Make an ICE chart for the solution of AgBr
"S" represents the molar solubility of AgBr
AgBr(s) ⇄ Ag⁺(aq) + Br⁻(aq)
I 0 0
C +S +S
E S S
Step 2: Write the expression for the solubility product constant (Ksp)
Ksp = [Ag⁺] [Br⁻] = S × S
Ksp = S² = (0.0007350)² = 0.000000540
Answer:
1.67mol/L
Explanation:
Data obtained from the question include:
Mole of solute (K2CO3) = 5.51 moles
Volume of solution = 3.30 L
Molarity =?
Molarity is simply the mole of solute per unit litre of the solution. It can be expressed mathematically as:
Molarity = mole of solute /Volume of solution
Molarity = 5.51 mol/3.30 L
Molarity = 1.67mol/L
Therefore, the molarity of K2CO3 is 1.67mol/L
