X=27 and y=11
if you let each number equal x and y we know the sum is 38 so x+y=38
and the smaller is 16 less than the larger
. so if we say the smaller number is 7 then x-16=y
these can be solved as a simultaneous equation. x+(x-16)=38
2x-16=38
2x=54
x=27
(27)-16=y
y=11
so the answer is x=27 y=11
Complete Questions:
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.
a. 40
b. 48
c. 56
d. 64
Answer:
a. 0.35
b. 0.43
c. 0.49
d. 0.54
Step-by-step explanation:
(a)
The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.
Let s be the sample space of all integer not exceeding 40.
The total number of ways to select 6 numbers from 40 is .
Let E be the event of selecting none of the correct six integers.
The total number of ways to select the 6 incorrect numbers from 34 numbers is:
Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is
Therefore, the probability is 0.35
Check the attached files for additionals
Answer:
1/4
Step-by-step explanation:
3/12 =0.25
0.25 = 1/4
Since the formula for the base of the cylinder is
, multiplying that by 10 we get
. Hope this helps!