Answer:
Step-by-step explanation:
To prove Δ ABC similar to ΔDBE we can consider
Segments AC and DE are parallel.
⇒ DE intersects AB and BC in same ratio.
AB is a transversal line passing AC and DE.
⇒∠BAC=∠BDE [corresponding angles]
Angle B is congruent to itself due to the reflexive property.
All of them are telling a relation of parts of ΔABC to ΔDBE.
The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".
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There are 24 possible answers, 6 are correct answers and 18 are incorrect answers. By use of the hypergeometric distribution the probabilities of each possible number of randomly selected correct answers can be found, as follows:
P(0) = 0.1379, P(1) = 0.3819, P(2) = 0.341, P(3) = 0.1213, P(4) = 0.017, P(5) = 0.0008, P(6) = 0.000007.
The expected or mean number of correct answers is found from:
The answer is: 1.4998
Answer:
x = 5
Step-by-step explanation:
Note the equal sign, what you do to one side, you do to the other. Isolate the variable, x.
Add 3 and subtract 2x from both sides of the equation:
4x (-2x) - 3 (+3) = 2x (-2x) + 7 (+3)
4x - 2x = 7 + 3
2x = 10
Next, isolate the x by dividing 2 from both sides of the equation:
(2x)/2 = (10)/2
x = 10/2
x = 5
5 is your answer for x.
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Answer:
<u>y=5x-7</u>
Step-by-step explanation:
1. First the slope: -17-8/-2-3= -25/-5=5
2. What is your line equation now? y=5x+b
3. Replace the x and y value with one of the coordinate points: 8=5(3)+b
4. Solve for b: 8=15+b -7=b
5. Substitute it in the equation: y=5x-7
Hope this helps!
