Answer : The specific heat of the metal is, 
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of ice = 
= mass of metal = 1.00 kg
= mass of ice = 1.00 kg
= final temperature of mixture = 
= initial temperature of metal = 
= initial temperature of ice = 
Now put all the given values in the above formula, we get:
![(1.00kg)\times c_1\times (-8.88-5.00)^oC=-[(1.00kg)\times 2000J/kg^oC\times (-8.88-(-24.0))^oC]](https://tex.z-dn.net/?f=%281.00kg%29%5Ctimes%20c_1%5Ctimes%20%28-8.88-5.00%29%5EoC%3D-%5B%281.00kg%29%5Ctimes%202000J%2Fkg%5EoC%5Ctimes%20%28-8.88-%28-24.0%29%29%5EoC%5D)
Therefore, the specific heat of the metal is,
We have two sides and one angle opposite to one of the known sides.
Begin with applying the Law of Sines to find angle A:
= <span>
Then, solve for sin A:
</span>sin A =
Now, plug in numbers:
sin A = 19 × sin(38) / 10 = 1.17
We know that it does not exist an angle whose sin is bigger than 1, therefore
no triangle is formed.
So hmm the first term is -2
and if we divide one term by the term before it, we'd get the "common ratio" "r"
so hmm say -32/8 that gives us -4, so r = -4
thus
f(-10) = 4
f(-2) = 4
Since y is constant while x isnt we just dont need to put x
f(x) = 4
